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Old 09-19-2011, 11:32 PM   #1
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Method to the function range of the number of


Health physics and chemistry''blending palm in the Edition 'delete function Peng 7-8 is designed £+£+÷ eleven eleven ÷ (t - 1). +4 ≤ 4, so ∈ (a.., 43 Fourth, the discriminant function evaluation method rational fraction range of issues, if the denominator is a constant positive or constant negative quadratic trinomial, you can use the discriminant method. This is because it is equivalent to a quadratic equation in a real discussion focused on the conditions of solvability otherwise,Beats By Dre Headphones, will be discussed in a sub-set of real numbers of concentration of solvability of the problem, discriminant alone is not enough. seeking twelve 4 Y range. Solution: The original function can be turned into yx-4 + 5-4-o (easy to know that> o). discriminant △ one of its 16 one 4y (5 a 4) ≥ O, the solution was O ≤ ≤ 4 because y: fi: O, so the range of demand yE (O, 4]. five, changing element method for the mathematical element method in the learning process is widely used, the use of it can help us quickly from complex to simple solve the problem, such as demand dried form, such as day +6 (n,Oakley sunglasses sale, c ≠ o) range of functions,Salvatore Ferragamo outlet, in addition can be used with the method, discriminant method, it can also use the substitution method. demand function parameters-2-5 + /, two stone range. Solution: Let £ a 15-4 (£ ≥ o), then the t-154x, a ÷ (15 - t), into a function, we get: y = 2 · {(15 one £) a 5 + £ eleven-1tz + £ +5 eleven professionals (t - 1) +3 ≤ 3 (£ ≥ o )..'. function of the range is (a.., 3]. VI. inequality method using the formula for the mean average for the most ugly ≥ ± once the value must meet three conditions: ①, X2, ..., must be a positive real number; ② must ensure that a z a moment, the equality holds; ③ + z + ... + and X2 ... there is a constant, three are indispensable. ◆ function 1o (+ special) the range is --. solution: 1 ~ y = l 。(+{) the domain is R, the + { ≥ 2 · √ ·-4, available: Y a 1og Ji (+ special) ≤ 1o4 =-- 2,ed hardy uk, so yE (a ∞, a 2]. seven, the use of triangular grasshopper boundedness of the number of trigonometric functions of law boundedness: sinxI ≤ 1, COSXI ≤ 1 in the problem-solving has a wide range of applications. boundedness of trigonometric functions using the problem into a day si commanded +6 or Y = acosx + bsinx. Ba luxury value of the following functions domains: (I) a curly I (Ⅱ) y ~ COS2si topiramate. Solution: (I) was si an original style, because lSi1 ≤ 1, so ll ≤ 1, that is, l2 (1 a) 1 ≤ 11 + I. This inequality is equivalent to 4 (1 a) z ≤ (1 +), the solution of the obtained {≤ 3. (Ⅱ) as cOS2x = l-sin2.z ',herve leger toronto, so y =-- sin + sinx + l eleven ( sinx-1) + 4 * once another 1 ≤ i1, then at ≤ si a 11, so. ≤ (si a special) ≤ number. so (at) + {≤ {, that is a function of the range is [ ,],[X2) + (a ~/,) 1, <<a2; 0
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Old 09-19-2011, 11:46 PM   #2
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