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滋阴的十大宝物,为妻子保藏了 - Qzone日记
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Reprinted from alumni of the user at 07:56 on October 10, 2010 Read (loading. ..) Comments (0) Category: Personal Diary
1, ten by ten: -
formulas: the head by head, tail plus tail, tail by tail. -
Example: 12 × 14 =? -
solution: 1 × 1 = 1 -
2 +4 = 6 -
2 × 4 = 8 -
12 × 14 = 168 -
Note: a bit multiply, not use the 0 digit placeholder. -
-
2. head the same, complementary tail (tail add up to 10 ):-
formulas: a first add 1 to the head by head, tail by tail. -
Example: 23 × 27 =? -
Solution: 2 +1 = 3 -
2 × 3 = 6 -
3 × 7 = 21 -
23 × 27 = 621 -
Note: a bit multiply, not use the 0 digit placeholder. -
-
3, the first multiplier complementary, the same as the other multiplier: -
formulas: a first add 1 to the head by head, tail by tail. -
Example: 37 × 44 =? -
solution: 3 +1 = 4 -
4 × 4 = 16 -
7 × 4 = 28 -
37 × 44 = 1628 -
Note: a bit multiply, not use the 0 digit placeholder. -
-
4, dozens of dozens of one by one: -
formulas: head by head, head plus head, tail by tail. -
Example: 21 × 41 =? -
solutions: 2 × 4 = 8 -
2 +4 = 6 -
1 × 1 = 1 -
21 × 41 = 861 -
-
5,11 by any number: -
formulas: sum of fixed fate, and the middle of the drop-down. -
Example: 11 × 23125 =? -
Solution: 2 +3 = 5 -
3 +1 = 4 -
1 +2 = 3 -
2 +5 = 7 -
2 and 5, respectively, in the end to end -
11 × 23125 = 254375 -
Note: and over ten to get into one. -
-
6,
美妙的开始 - Qzone日志, a dozen by any number: -
formulas: the whereabouts of the second movement is not the first multiplier, the first digit multiplied by the factor behind the second factor of each number,
Men need a good woman - Qzone log, plus the next digit, again missing. -
Example: 13 × 326 =? -
solution: 13 bits is 3 -
3 × 3 +2 = 11 -
3 × 2 +6 = 12 -
3 × 6 = 18 -
13 × 326 = 4238 -
Note: and over ten to get into one. -
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