louis vuitton lightning rowdy understanding of lin

[cooly8393147]

Source: http://gliethttp.cublog.cn
Linux to based I / O charting of the I / O port and memory charting reach based on I / O port resources, collectively referred to as I / O Region). I / O Region is still an I / O resources, it can still be accustomed to describe the type of resource structure.
Linux is an inverted tree architecture to manage every type of I / O resources (such as: I / O ports, marginal memories, DMA and IRQ) for. each type of I / O resources are the resources corresponding to have an inverted tree, every knot in the tree is a resource building, and tree the root of the root of such resources is described in the resource space.
1. structure
1.1> struct resource iomem_resource = {1.2> struct resource {
const char * name;
unsigned long start, end;
unsigned long flags;
struct resource * parent, * sibling, * child;
2. Call function
request_mem_region (S1D_PHYSICAL_REG_ADDR, S1D_PHYSICAL_REG_SIZE, Check for safe occupancy later the start physical address S1D_PHYSICAL_REG_ADDR S1D_PHYSICAL_REG_SIZE successive bytes of space struct resource * __request_region (struct resource * parent, unsigned long start, unsigned long n, const char * label) struct resource * res = kmalloc (sizeof ( * res), GFP_KERNEL); if (res) {memset (res, 0, sizeof (* res)); res-> name = name; res-> start = start; res-> end = start + n - 1; res-> flags = IORESOURCE_BUSY; write_lock (& ​​resource_lock); for (;;) {struct resource * clash; conflict = __request_resource (parent, res); / / sibling parent under all element test for partly the subsistence of overlapping conflicts if (! conflict) / / conflict = 0; application is successful, the natural nestle of the [start,7名小学生欲办儿童版春晚 网帖直播筹备过程,coach bags, end] to the corresponding position destroy; if (conflict! = parent) {parent = conflict; if (! (conflict- > flags & IORESOURCE_BUSY)) proceed; kfree (res); / / resource overlap conflict is detected, kfree application for the return kmalloc memories res = NULL; crash; write_unlock (& ​​resource_lock); return res; static struct resource * __request_resource (struct resource * root, struct resource * new) unsigned long start = new-> start; unsigned long end = new-> end; struct resource * tmp, ** p; if (end begin) return basis; whether (end> root-> end) return root; p = & root-> baby; / / root ingredient under the premier list * p . [child list is based aboard I / O resources, physical residence from cheap to high in the order of] for (;;) {tmp = * p; if (,supra skytop ii gradient! tmp | | tmp-> start> end) {new- > brother = tmp; * p = new; / / from root-> child = null begin our inquiry, then tmp = null,Boy suffering from abnormal body seeking long- mole nowhere, then the premier applications ambition be! tmp conditions are met, and enter / / this time root-> child the merit of current arrows, new-> sibling = tmp = null; When the second applying occurs: If the tmp-> start> end set up, / / ​​then, root-> child's new pointer worth, new-> sibling = tmp; This link, and spatial distribution, such as: / / child = [start, end ]-->[ tmp-> start, tmp-> end] (1); If the conditions tmp-> start> end does not prop, then only! tmp conditions of access / / Well, root-> child the value of the constant, tmp-> sibling = new; new-> sibling = tmp = null This link, and spatial delivery, such as: / / child = [child-> start,supra fashion, child-> end ]-->[ start, end] (2); / / When the premier time of 3 applications: If you start in (2) of the [child-> end, end], between then tmp-> end start slibing = null, / / ​​because the tmp-> end> ​​start, so the resource conflict, return ( 2) the [start, end] domain / / amount of the two boundary conditions and a centre value of the analysis, we tin discern a code to address to high address from the order of list / / model diagram: childe = [a, b ]-->[ c, d ]-->[ e, f], then there is a [x, y] to be inserted into, tmp as a sibling pointer swimming / / tmp point to the child = [ ,],[> [c, d ]-->[ e, f] -> null; when tmp-> end> ​​= x, the conflict to return tmp / / tmp point to [c, d],louis vuitton speedy, if tmp-> ; start> y, insert the link after the photo: child = [a, b ]-->[ x, y ]-->[ c, d ]-->[ e, f] -> ; null; while tmp-> end> ​​= x,市民酒后5倍投注双色球撞中3304万, the conflict to return tmp / / tmp point to [e, f], if tmp-> start> y,asics kayano 15, insert the link after the photo: child = [a, b ]-->[ c, d ]-->[ x, y ]-->[ e, f] -> null; when tmp-> end> ​​= x, the conflict to return tmp / / tmp point to null, insert the link after the photo: child = [a, b ]-->[ c, d ]-->[ e, f ]-->[ x, y] -> null ; / / smooth to the observation of conflict, the intention of the order link new-> parent = root; return NULL; p = & tmp-> sibling; if (tmp-> end <start) continue; return tmp ; article from CSDN blog, reproduced, please credit: http://
HW: test the water to enter the electronic schooling mall Baidu response: three days to handle with entire written documents and Baidu infringement battle of 2 artists who YouTube alternatively re-position mutual adventure co-founder of Google founders Page start afterward month, got rid of bureaucracy as CEO of the multi-threading capabilities Silverlight (beneath) using Myisamchk therapeutic exam of the MySQL charts Silverlight 2.5D RPG gaming skills and effects processing: (vii) Animated Feature Tour VS2010 test function: coded UI test (4) - the direction at manuscript test code create UI tests (underneath) for more articles ... China-pub Knowledge of computer books online cache! 65,000 varieties of 2 - 8 off! China-Pub-demand printing services microcomputer publish books under the request_mem_region rowdy understanding of linux android developer (4) bootloader (1) linux driver (17) mobile developer (1) my linux device driver (1) 2011 年 3 months ( 6) February 2011 (2) January 2011 (7) December 2010 (5) November 2010 (2) October 2010 (8) August 2010 (3) 1. Android JNI Knowledge About (824) 2. Android Development Notes Programming Example of a NDK (511) 3. Linux device driver development context set up (rotate) (273) 4. socket and multi-thread programming basics portability (transmit) (221) 5. Android TQ2440 development embark in the transfer (transfer) (203) 1. Android JNI Knowledge About (0) 2. Android Development Notes Programming Example of a NDK (0) 3. Android evolution board in the TQ2440 transplantation (transfer) (0) 4. ARM assembler programming (0) 5. c language static usage summary (0) 1. Linux device driver wafer design (transfer) (63) 2. platform_device and platform_driver (47) 3. S3C2440 RTC clock on driven development instance to explain (to) http://hbhuanggang.cublog.cn (30) 4. ic_card Driver Development (7) 5. static Usage (4)