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Pit floor slab loads of non-uniform surface when the force analysis


ig. 6InternalforceofbeamE-F A-A beam with the force at the intersection of (1-good) P, and B-B beam intersection by the force of a p, then f: (2 Health 2 (Mo 2: + (B! Mawson,tory burch outlet! : .243 EI. 486EI 'Factory D = 243E +486. Jl' by the - beam and E-F beam deflection equal to the intersection of C available: 15kpL-4 (1-k) p (nL) J.7 (a p]! Health 486243E1486 solve this simultaneous equations was 8713-15 +-18n3. 8n, Il5 + I1578n, l + n, 37nll157: 8n, I a + ln +8 n Korea 7nn + l6n '+ l5 when to, l assigned to specific data, k, values ​​in Table l. Table l solution of the beam calculated Nei Lizhi Table 2 Table 1 Commonly used force coefficient Table1Commoninternalforcefactors0.60.096p0.032pL0. 082p0.80.186p0.062pL0.153p1.00.281P0 .093 pL0.219p1.20.368p0.123pL0.265p1.40.444pI1148pL0.28 9p1.6O.509pO.170pL0.295p0.027pL0.051pL0.073pL0.088 pL0.096pL0.098pL0.575p0.115pL0.247pO.0494pL0.492p0 .13lpL0 .169 pO.0452pL0.406p0.135pL0.094pO.0312pL0.333p0.133pL0 .034p0.0136pL0.274p0.128pL0.0073p0.oo342pL0.2291) O.122pL a 0.033p-o.o176pL3 forces with the approximate method to simplify the load into all cloth load q = p / ab, check the (1) 4 B-B analyzed by the beam and E-F beam node D can get 151tpL a deflection equal to 4 (a p) (, lL) J. two Fort! (ink!: 486,243,486 simplification was: 7nk + ( 15 +8 n) = 7n. (2) of Table 2, Table 3 Nei Lizhi both cases a comparison of Table 4 shows the ratio of forces from the table: calculation by approximation of beam with load at node D consideration, the actual load is not so much the beam is too large and uneven distribution of Nei Lizhi, especially when,ed hardy canada, l is large, 34 Heilongjiang College of Science and Technology Volume 12 Pit Table 3 Nei Lizhi beam within the beam system Table3Internalforcesvalueofeachbeaminwellbeamsyste m Table 4 Nei Lizhi comparison Table4comparativeresultofinternalforcesvalueB-B beam moment is too large a 2.724-fold,air jordan high heels, while the E-F beam is too small a O.123-fold; beam shear values ​​generally too large 1.847-5.260 times so in the actual project will waste a lot of material, increase the project cost. and when n = 1.4-1.6, when, E-F beam moment at point C is less than the actual moment, and point D has a negative bending moments, beam safety compromised. 5 according to the practical application of structural strength calculations, the workload,mulberry outlet, there are two solutions: First, the preparation of the corresponding procedures, load factors calculated by computer; second, according to the manual method the preparation of the corresponding form for the designer access. seen from Table 5, when the A-A beam on the role of cable load, with P = qab conversion, and M-fold increase O.125, shear Q O.5-fold increase. Table 5 Nei Lizhi Table5Internalforcesvalueofwellbeamsystem Pit beam system for several years, actual engineering design in the application of the method of calculation, the statistical Pit beam reinforcement system reduced by 30% to 60%, economic benefits are considerable. References [ ],[He graduated from Harbin Institute of Construction, is mainly engaged in structural design.
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